RE: [ECOS] A simple data type question

["Trenton D. Adams" <tadams at extremeeng dot com>]

It all depends on the word size of your platform.  If you have a 32 bit
word, then unsigned should be a 32-bit unsigned integer.  If however
your word is 16-bits, then unsigned would be 16-bit.  I suppose it could
depend on the compiler too, but I think it's a standard to go by the
word size of the CPU in use.

Since a #define is just a macro, and replaces any place it occurs with
the defined statement, you would have to use a type cast like the
example you gave.  So, if your CPU uses a 16-bit word, then you would
need to go 

#define IOPDATA          ((unsigned long *)0x0)

Someone tell me if I'm wrong! :)

-----Original Message-----
From: ecos-discuss-owner@sources.redhat.com
[mailto:ecos-discuss-owner@sources.redhat.com] On Behalf Of HuangQiang
Sent: Tuesday, June 12, 2001 2:57 AM
To: eCos
Subject: [ECOS] A simple data type question


Hi all:
   Could anyone give me some detail about the following statement:

	#define IOPDATA		((volatile unsigned *)(SYSCFG + 0x5008))

if I change the *IOPDATA = 0x0; then how many bit can I change . what
data width is the (volatile unsigned *)? if I want to use a 32-bit width
pointer how can I do it?

Thanks all.