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Re: therad delay problem


On Tue, Nov 25, 2003 at 10:59:06AM +0530, Aravind B wrote:
> hi,
> 	i have written a program which contains  3 thread as  shown.
> 
> cyg_user_start(void)
> {
> 
> printf("entering two threads cyg_user_start() function\n");
> 
> cyg_mutex_init(&cliblock);
> 	cyg_thread_create(3,simple_program,(cyg_addrword_t)2,
> 	"simple_program_Thread ",(void*) stack[2],4096,
> 	 &simple_program_Thread,&thread_s[2]);
> 	cyg_thread_create(4,simple_program1,(cyg_addrword_t)3,
> 	"simple_program1_Thread",(void*) stack[3],4096,
> 	 &simple_program1_Thread,&thread_s[3]);
> 	 cyg_thread_create(5,simple_program2,(cyg_addrword_t)4,
> 	"simple_program2_Thread",(void*) stack[4],4096,
> 	 &simple_program2_Thread,&thread_s[4]);
> 
> cyg_thread_resume(simple_program_Thread);
> cyg_thread_resume(simple_program1_Thread);
> cyg_thread_resume(simple_program2_Thread);
> }
> cyg_alarm_t alarm_Tbcn_func;
> 
> void simple_program(cyg_addrword_t data )
> {
> 	int message=(int) data;
> 	unsigned int i;
> 	printf("i am thread %d before delay\n",message);
> 
> 	curr_time=cyg_real_time_clock();
> 	cyg_clock_to_counter(curr_time,&handle_counterTbcn);
>         cyg_alarm_create(handle_counterTbcn, alarm_Tbcn_func,5500,
>                 	&handle_alarmTbcn, &alarm_Tbcn);
> 	cyg_alarm_initialize(handle_alarmTbcn,cyg_current_time()+200,0);
> 
> 		cyg_thread_delay(3);
> 		while(1)
> 		{
> 			if(var==1)
> 			{
> 				printf(" hello");
> 				break;
> 			}
> 		}
> }
> 
> void  simple_program1(cyg_addrword_t data )
> {
> 	int message=(int) data;
> 	printf("i am thread %d\n",message);
> }
> 
> void  simple_program2(cyg_addrword_t data )
> {
> 	int message=(int) data;
> 	printf("i am thread %d\n",message);
> 	while(1)
> 	{
> 	}
> }
>  void alarm_Tbcn_func( cyg_handle_t alarmTbcn,cyg_addrword_t data)
> {
> 	var=1;
> 	printf(" i am  in alarm function\n");
> }
> 
> 
> there is cyg_thread _delay(3) in t1.the control goes to t2 and then
> t3.In t3 i have infinite while loop.The control is not going to t1.Is
> there any way so that i can signal to t1 that thread delay is over and
> it can continue its flow.If so then how it is? 

Does the alarm hander get called?

it var a volatile?

   Andrew

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