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Dual Port RAM on MPC8xx


I'm trying to understand how the allocation of DPRAM is done in the function _mpc8xx_allocBd in cpm.c.

Can someone explain why nextBD is initialised as:

static short *nextBd = (short *)(CYGHWR_HAL_VSR_TABLE + 0x1F0);

Presumably this is so that redboot and an application can cooperate when using the DPRAM? Why is this address chosen and when is it's contents ever initialised?

Presumably it may not have been initialised as in _mpc8xx_allocBd there is this code:

    if ((bd < QUICC_BD_BASE) || (bd > QUICC_BD_END)) {
        // Most likely not set up - make a guess :-(
        bd = *nextBd = QUICC_BD_BASE+0x400;
    }

I guess this is starting 0x400 into the DPRAM so that an apllication doesn't reuse any DPRAM used by redboot? Is this correct? I can find where redboot ever initialises this memory so I can't see how it works.

Any help in understanding this is much appreciated.

Will Wagner


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