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redboot startup mode


hi,
i have a doubt/question?

i'm trying to compile a redboot in romram mode.


At http://sources.redhat.com/ecos/docs-latest/redboot/excaliburarm9.html

say that romram mode runs redboot from ram with redboot in flash. I supossed
that redboot is stored in flash memory and then it is copied from flash to ram.
But when i desassemble the file i get the code is mapped on ram (0x8000):

redboot.elf:     file format elf32-littlearm

Disassembly of section .rom_vectors:

00008000 <__exception_handlers>:
    8000:	ea00000e 	b	8040 <_stext>
    8004:	e59ff018 	ldr	pc, [pc, #24]	; 8024 <.undefined_instruction>
    8008:	e59ff018 	ldr	pc, [pc, #24]	; 8028 <.software_interrupt>
    800c:	e59ff018 	ldr	pc, [pc, #24]	; 802c <.abort_prefetch>
    8010:	e59ff018 	ldr	pc, [pc, #24]	; 8030 <.abort_data>
    8014:	00000000 	andeq	r0, r0, r0
    8018:	e59ff018 	ldr	pc, [pc, #24]	; 8038 <.IRQ>
    801c:	e59ff018 	ldr	pc, [pc, #24]	; 803c <.FIQ>

00008020 <vectors>:
    8020:	00000040 	andeq	r0, r0, r0, asr #32

00008024 <.undefined_instruction>:
    8024:	00008494 	muleq	r0, r4, r4

00008028 <.software_interrupt>:
    8028:	000084b8 	streqh	r8, [r0], -r8

etc....

Maybe i don`t  understand this mode at all.

thanks.

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