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Hi! On Sun, 01 Jul 2012 10:24:33 -0700, Russ Allbery <rra@stanford.edu> wrote: > "Joseph S. Myers" <joseph@codesourcery.com> writes: > > On Sun, 1 Jul 2012, Joseph S. Myers wrote: > > >> I've pushed the glibc-ports-merge branch that has the contents of the > >> ports repository in the ports/ directory. Please review this and see > >> if it is as you expect. Confirming that the branch/tag is identical to what you get from the 2.16.0 *.xz tarballs from <ftp://ftp.gnu.org/gnu/glibc/>. > >> There is a tag glibc-2.16-ports-merge at the > >> tip of the branch; that tip revision is expected to become the tip of > >> master if the merge is OK. > > > I should add: I believe > > > git push origin glibc-ports-merge:refs/heads/master Even Âgit push origin [...]:master works (I use this all the time), as there already is a master branch existing, and then Git knows what is meant. > > is the right way to make this tagged merge commit appear on master, but > > let me know if there's something wrong with that. > > This does an implicit fast-forward merge of your local glibc-ports-merge > branch to master in the remote repository. It's okay to do it this way, > but it's mildly confusing (to me at least). I would instead do: > > git checkout master > git merge glibc-ports-merge > > locally, ensure that Git says that the merge is a fast-forward merge, and, > if it does, push your master to the remote repository the way that you > normally would. But that's always going to give the exactly same results, in my understanding? What distinction are you out for? GrÃÃe, Thomas
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